WAP in JAVA to check whether a number is armstrong or not
import java.util.*;
class loop{
public static void main(String args[])
{
int a,s=0,n;
Scanner ob=new Scanner(System.in);
System.out.println("enter the no:");
n=ob.nextInt();
while(n!=0)
{
a=n%10;
s=s+(a*a*a);
n=n/10;
}
System.out.println(+s);
if(n==s)
System.out.println("armstrong no");
else
System.out.println("not armstrong");
}
}
class loop{
public static void main(String args[])
{
int a,s=0,n;
Scanner ob=new Scanner(System.in);
System.out.println("enter the no:");
n=ob.nextInt();
while(n!=0)
{
a=n%10;
s=s+(a*a*a);
n=n/10;
}
System.out.println(+s);
if(n==s)
System.out.println("armstrong no");
else
System.out.println("not armstrong");
}
}
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