JAVA PROGRAMMING

Sum of the series (1/1!)+(1/2!)+(1/3!)+...+(1/n!) in Java /*Problem: Write a program in Java to find the sum of the series  * using function name fact(int) to return the factorial  * of the number in order to obtain each term.  * The series :-  * S=(1/1!)+(1/2!)+(1/3!)+...+(1/n!)  */ import java.util.*; class series2 {     public static void main()     {         System.out.print("Enter the value of n : ");         Scanner sc=new Scanner(System.in);         int n,i;         n=sc.nextInt();         double S=0,f=0;         for(i=1;i<n;i++)         {             f=fact(i);             S=S+(1/f);         }         System.out.println("The sum ="+S);     }         public static double fact(int num)     {         int f=1,j;         for(j=1;j<=num;j++)         {             f=f*j;         }         return(f);     } }

Write two separate programs to generate the following patterns using iteration(loop) statements : (a) (b) class Pattern1 { public static void main(String args[]) { for(int i=1;i<=5;i++) { for(int j=1;j<=i;j++) { if(j%2!=0) System.out.print (“* “); else System.out.print (“# “); } System.out.println (); } } } class Pattern2 {     public static void main(String args[]) { int k = 5; for(int i=5;i>=0;i–) { k=5; for(int j=i;j>=0;j–) { System.out.print(k +” “); k–; } System.out.println (); } } }